$A$ student focused the image of a candle flame on a white screen by placing the flame at various distances from a convex lens. He noted his observations:
ObservationDistance of flame from the lens $(cm)$Distance of screen from the lens $(cm)$
$(i)$$60$$20$
$(ii)$$40$$24$
$(iii)$$30$$30$
$(iv)$$24$$40$
$(v)$$15$$70$

$(a)$ From the above table, find the focal length of the lens without using the lens formula.
$(b)$ Which set of observations is incorrect and why?
$(c)$ In which case will the size of the object and the image be the same? Give a reason for your answer.

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(N/A) From the table of observations, it is clear that for observation $(iii)$, $u = 30 \, cm$ and $v = 30 \, cm$. This means that both $u$ and $v$ are equal to twice the focal length $(2f)$ of the convex lens.
Therefore, $2f = 30 \, cm$, which gives the focal length $f = 15 \, cm$.
$(b)$ The observation $(v)$ is incorrect. For this observation, $u = 15 \, cm$, which is equal to the focal length $(f = 15 \, cm)$. When an object is placed at the focus of a convex lens, the image is formed at infinity, not at $70 \, cm$.
$(c)$ The size of the image is equal to the size of the object when the magnification $m = 1$. Since $m = \frac{v}{u}$, the size of the image will be equal to the size of the object if $v = u$. This occurs in observation $(iii)$, where $u = 30 \, cm$ and $v = 30 \, cm$.

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$A$ student focussed the image of a candle flame on a white screen using a convex lens. He noted down the position of the candle,screen,and the lens as under:
Position of candle $= 12.0\, cm$
Position of convex lens $= 50.0\, cm$
Position of the screen $= 88.0\, cm$
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$(ii)$ What will be the nature of the image formed if he further shifts the candle towards the lens?
$(iii)$ Draw a ray diagram to show the formation of the image in case $(ii)$ as said above.

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